• Glitchvid@lemmy.world
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    8 days ago

    It’s an understandable interpretation for the lexical use of or which can imply exclusive disjunction.

    In Rust the result type has the method .or() which returns either Ok(A) or Ok(B) (but not both), and I don’t see clambering to change it to xor, because the exclusive nature is implicit both linguistically and in the type state.

    • Asetru@feddit.org
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      7 days ago

      The result type in rust does not return a true/false but a type. More importantly though, it doesn’t return err if both values are set but simply returns the first value:

      So… It’s not only not mapping your input to truth values, it also behaves more like I’d expect an “or” to behave, which is not “xor” or, if there’s more than two inputs, “exactly one”, but succeeding if any input is set.

      • Glitchvid@lemmy.world
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        5 days ago

        …Which is basically how the OP’s or function also works, it takes several Option<T>s and returns the first valid one (and only that one), it doesn’t operate on boolean logic types — it’s a valid lexical use of or.

        • Asetru@feddit.org
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          5 days ago

          Absolutely not.

          Mutually exclusive options

          Another classic. Pick one output format: JSON, YAML, or XML. But definitely not two.

          Emphasis mine.

          It takes the input and fails if there is more than one valid one, which decidedly isn’t what’s an “or” in comp sci.