• corvus@lemmy.ml
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    1 hour ago

    Chicken thinking: “Someone please explain this guy how we solve the Schroëdinger equation”

    • marcos@lemmy.world
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      3 hours ago

      And it denotes an operation that gives you that fraction in operational algebra…

      Instead of making it clear that d is an operator, not a value, and thus the entire thing becomes an operator, physicists keep claiming that there’s no fraction involved. I guess they like confusing people.

  • chortle_tortle@mander.xyz
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    9 hours ago

    Mathematicians will in one breath tell you in one breath they aren’t fractions, then in the next tell you dz/dx = dz/dy * dy/dx

  • rudyharrelson@lemmy.radio
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    12 hours ago

    Derivatives started making more sense to me after I started learning their practical applications in physics class. d/dx was too abstract when learning it in precalc, but once physics introduced d/dt (change with respect to time t), it made derivative formulas feel more intuitive, like “velocity is the change in position with respect to time, which the derivative of position” and “acceleration is the change in velocity with respect to time, which is the derivative of velocity”

    • Prunebutt@slrpnk.net
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      10 hours ago

      Possibly you just had to hear it more than once.

      I learned it the other way around since my physics teacher was speedrunning the math sections to get to the fun physics stuff and I really got it after hearing it the second time in math class.

      But yeah: it often helps to have practical examples and it doesn’t get any more applicable to real life than d/dt.

  • vaionko@sopuli.xyz
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    12 hours ago

    Except you can kinda treat it as a fraction when dealing with differential equations

  • benignintervention@lemmy.world
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    13 hours ago

    I found math in physics to have this really fun duality of “these are rigorous rules that must be followed” and “if we make a set of edge case assumptions, we can fit the square peg in the round hole”

    Also I will always treat the derivative operator as a fraction

  • iAvicenna@lemmy.world
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    10 hours ago

    Look it is so simple, it just acts on an uncountably infinite dimensional vector space of differentiable functions.

  • Zerush@lemmy.ml
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    10 hours ago

    When a mathematician want to scare an physicist he only need to speak about ∞

    • corvus@lemmy.ml
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      53 minutes ago

      When a physicist want to impress a mathematician he explains how he tames infinities with renormalization.