• psud@aussie.zone
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    6 hours ago

    The acceleration will be 1G minus drag. The Earth is sufficiently larger than anything one would drop off a tower so the weight of the dropped thing doesn’t matter at all

    How does your model of the universe explain the hammer and feather dropped on the moon by Apollo 15’s David Scott landed at the same time?

    Ed. There is an effect of buoyancy that will make denser things fall faster. It becomes noticeable in distances where the dropped items reach terminal velocity or on more dense media where buoyancy is more significant.

    In air over short distances buoyancy is negligible, in vacuum there is none

    • missingno@fedia.io
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      7 hours ago

      minus drag

      On Earth, this is the part that makes it so that objects do not fall at the same speed.

      on the moon

      This is the type of experiment they could not do 2000 years ago.

      • psud@aussie.zone
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        4 hours ago

        minus drag

        On Earth, this is the part that makes it so that objects do not fall at the same speed.

        That is incorrect. Drag affects both equally. The difference is caused by buoyancy, less dense objects feel more buoyancy

        • Rivalarrival@lemmy.today
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          3 hours ago

          Buoyancy is functionally irrelevant here. Buoyancy in air effectively subtracts 1.3kg per cubic meter of each substance: The mass of the volume of air displaced by the object.

          The part you are not understanding: Drag applies the same force to both objects. Gravity applies the same acceleration to each object.

    • mnemonicmonkeys@sh.itjust.works
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      7 hours ago

      The Earth is sufficiently larger than anything one would drop off a tower that the weight of the dropped thing doesn’t matter at all

      F=ma.

      Two items of the same shape will have the same amount of air resistance. If they have significantly different masses, the two object experience commensurately different accelerations (or reduction in acceleration), even if the force is the same.

      If you take a balloon full of tetrahexofluroride (a gas 6x the density of air) and a chunk of iron the exact same size and shape and throw them off a building, I guarantee the iron chunk will hit first.

      How does your model of the universe explain the hammer and feather dropped on the moon by Apollo 15’s David Scott landed at the same time?

      It’s called a vacuum, which is famous for not having air resistance. Y’know, the thing we’re talking about?

      To perform the experiment properly on Earth where there is air resistance, you need to pick a shape and range of masses that minimize the effect of air resistance

    • Rivalarrival@lemmy.today
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      6 hours ago

      Read their claim again: they are specifically describing the effect of air resistance. Their claim is perfectly consistent with the lunar feather/hammer experiment.

      • psud@aussie.zone
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        4 hours ago

        Their problem was that they weren’t able to say why, and no one replying to me was able to do more than say they’re right, I’m wrong. See my edit. I added a correction after looking up drag equations for myself and finding that buoyancy was a factor

        Also, thank you for replying civilly

        • Rivalarrival@lemmy.today
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          3 hours ago

          They did. You didn’t understand what they said.

          Two items of the same shape will have the same amount of air resistance. If they have significantly different masses, the two object experience commensurately different accelerations (or reduction in acceleration), even if the force is the same.

          The “same force” they are talking about is drag. The two objects are the same size and shape. At the same velocity, drag affects them both equally, applying an equal, upward force against both objects.

          Gravity (in a vacuum) accelerates both objects equally. But they have differing masses. F=MA. F/M = A. A is equal for both objects. Because acceleration is equal, the “force” on each object is not: the force must be proportional to its mass: The high mass object must be experiencing high force; the low-mass object must be experiencing low force.

          Subtract the “same force” of drag from the downward force on both objects, and the net force on each object is no longer proportional to the mass of each object. Consequently, the high-mass object accelerates in atmosphere faster than the low-mass object. The high-mass object has a higher terminal velocity; the low-mass object has a lower terminal velocity.

          For the purposes of this experiment, buoyancy is functionally irrelevant. The effect of buoyancy is to subtract a fixed mass from each object: A mass equivalent to the mass of air displaced by the object. Effectively, buoyancy slightly reduces the density of both objects. The actual difference in the densities of the two objects is far greater than the slight change due to buoyancy in air, so buoyancy is not a significant factor.